
 The matrix  mA 

  1/3    3/2    0/1   -1/2    1/2  
  0/1    4/1    3/2   -1/2   -2/1  
 -2/3    1/5    2/1    1/2    3/2  
  3/1   -4/2    2/1   -1/1   -4/2  
  1/2    3/4    1/1   -1/1    1/1  

 The matrix  mA_ID 

  1/3    3/2    0/1   -1/2    1/2    1/1    0/1    0/1    0/1    0/1  
  0/1    4/1    3/2   -1/2   -2/1    0/1    1/1    0/1    0/1    0/1  
 -2/3    1/5    2/1    1/2    3/2    0/1    0/1    1/1    0/1    0/1  
  3/1   -4/2    2/1   -1/1   -4/2    0/1    0/1    0/1    1/1    0/1  
  1/2    3/4    1/1   -1/1    1/1    0/1    0/1    0/1    0/1    1/1  

 Use GaussJordan  function to find the inverse of mA 

1/1 0/1 0/1 0/1 0/1 13641/8896 -33/139 2265/8896 1635/4448 -3951/4448 
0/1 1/1 0/1 0/1 0/1 2735/4448 10/139 415/4448 5/2224 -665/2224 
0/1 0/1 1/1 0/1 0/1 -3211/8896 17/139 2245/8896 295/4448 797/4448 
0/1 0/1 0/1 1/1 0/1 12995/8896 -23/139 5875/8896 1089/4448 -6949/4448 
0/1 0/1 0/1 0/1 1/1 5283/8896 -31/139 1875/8896 -31/4448 -325/4448 

The inverse matrix is : 

 13641/8896     -33/139     2265/8896    1635/4448   -3951/4448  
  2735/4448      10/139      415/4448       5/2224    -665/2224  
 -3211/8896      17/139     2245/8896     295/4448     797/4448  
 12995/8896     -23/139     5875/8896    1089/4448   -6949/4448  
  5283/8896     -31/139     1875/8896     -31/4448    -325/4448  

 mA * minv give 

  1/1    0/1    0/1    0/1    0/1  
  0/1    1/1    0/1    0/1    0/1  
  0/1    0/1    1/1    0/1    0/1  
  0/1    0/1    0/1    1/1    0/1  
  0/1    0/1    0/1    0/1    1/1  

 Press a key to continue